How do you calculate the total resistance of three resistors in series with values of 2Ω, 4Ω, and 6Ω?

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Enhance your preparation for the NEIEP Power and Logic (700) Test. Benefit from interactive multiple choice questions, detailed explanations, and comprehensive study resources. Get ready for your certification exam!

To find the total resistance of resistors connected in series, you simply add the resistance values of the individual resistors together.

In this case, you have three resistors with values of 2Ω, 4Ω, and 6Ω. The calculation is as follows:

Total Resistance = R1 + R2 + R3

Total Resistance = 2Ω + 4Ω + 6Ω

Total Resistance = 12Ω

This method is based on the principle that in a series circuit, the current through each resistor is the same, and the total resistance is the sum of the individual resistances. The correct answer demonstrates this straightforward addition, confirming that the total resistance of the three resistors is 12Ω.

How do you calculate the total resistance of three resistors in series with values of 2Ω, 4Ω, and 6Ω?

Enhance your preparation for the NEIEP Power and Logic (700) Test. Benefit from interactive multiple choice questions, detailed explanations, and comprehensive study resources. Get ready for your certification exam!

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